jQuery .find()
Learn all about the jQuery function .find().
Given a jQuery object that represents a set of DOM elements, the .find()
method allows us to search through the descendants of these elements in the DOM tree and construct a new jQuery object from the matching elements. The .find()
and .children()
methods are similar, except that the latter only travels a single level down the DOM tree.
The first signature for the .find()
method accepts a selector expression of the same type that we can pass to the $()
function. The elements will be filtered by testing whether they match this selector.
Consider a page with a basic nested list on it:
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2
3
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5
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7
8
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If we begin at item II, we can find list items within it:
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The result of this call is a red background on items A, B, 1, 2, 3, and C. Even though item II matches the selector expression, it is not included in the results; only descendants are considered candidates for the match.
Unlike most of the tree traversal methods, the selector expression is required in a call to .find()
. If we need to retrieve all of the descendant elements, we can pass in the universal selector '*'
to accomplish this.
Selector context is implemented with the .find()
method;
therefore, $( "li.item-ii" ).find( "li" )
is equivalent to $( "li", "li.item-ii" )
.
As of jQuery 1.6, we can also filter the selection with a given jQuery collection or element. With the same nested list as above, if we start with:
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And then pass this jQuery object to find:
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This will return a jQuery collection which contains only the list elements that are descendants of item II.
Similarly, an element may also be passed to find:
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The result of this call would be a red background on item 1.